Testing

Sunday, November 27, 2016

Concrete Mix Design 16 MPA


Concrete Mix Design 16 MPa

(Fcr = 0.9Fc+2.3S

Fcr = Design Compressive Strength of Concrete

Fc = Characteristics compressive strength of Concrete

S = Standard Deviation

If the data of Standard deviation is not available then we will use this equation

Fcr = Fc+ 10MPa)

Fcr = 16+10
Fcr= 26MPa

Strength = 36 MPa
Cement = OPC ( Ordinary Portland Cement)
Fine Aggregate = Natural Sand and Crush sand
Fine Aggregate fine Modulus = 2.7 23
FA Specific Gravity  = 2.602
FA absorption = 2.60

(CA)Coarse Aggregate NMS = 19 mm
CA Specific Gravity =  2.619
Absorption = 1.123
Dry density = 1510 kg/m3

Step No 1

 Selection of Slump and compressive Strength
Slump = 80 mm
Compressive strength


Fcr = Fc + 10 MPa

Fcr = 16+10

Fcr= 26 MPa

Step 2
Selection of Coarse aggregate proportion

NMS = 19 mm
So from table 8 when Nominal Max size is 19 then CA Volume = 0.64

Weight of Coarse Aggregate = 0.64*1510 =  966.4

Step 3
Calculation of water Cement and Air Content
From  table 2 & 3 when NMS =19mm then
Water = 205 Kg
Air content = 2%
Selection of w/c ratio
From table 6 when compressive strength = 26 MPa
Then w/c = 0.57

Step 6
Calculation of Cement Content
Weight of Cement = 205/0.57   = 359 kg/m3
Step No 7
Calculation of  Volume of All mix Ratios
Volume of cement = Wt of Cement/ Specific gravity (C/γc)
                                =359/3.15*1000            =  0.1139638

Volume of  Water =  Mixing water / Sp g * 1000
                                
= 205/1*1000                     =0.205
                                                                                     

Absolute Volume of Coarse Aggregate = 966.4/2.619*1000  = 0.368899
                                                                                 
Volume of Air = 2/ 10000           =0.002                     
                                                                                    

Total Absolute volume             =0.6898628


Wt of Fine Aggregate
 =1- Summation of Volume of Cement, Water                                                      Coarse aggregate

              =1 – 0.6898628
              =0.310372
Wt of Fine Aggregate = Volume of Fine aggregate * Sp gravity*1000
                                      = 0.33501*2.602*1000
                                     = 871 kg
Trail Batch
So Finally we will get these weight for trail either in laboratory or batching Plant

Cement                 = 410 Kg
Water                    =164 kg
Coarse Aggregate  =966.4 kg
Fine Aggregate       =871 kg

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